8j^2-5=27

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Solution for 8j^2-5=27 equation:


Simplifying
8j2 + -5 = 27

Reorder the terms:
-5 + 8j2 = 27

Solving
-5 + 8j2 = 27

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 8j2 = 27 + 5

Combine like terms: -5 + 5 = 0
0 + 8j2 = 27 + 5
8j2 = 27 + 5

Combine like terms: 27 + 5 = 32
8j2 = 32

Divide each side by '8'.
j2 = 4

Simplifying
j2 = 4

Take the square root of each side:
j = {-2, 2}

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